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itsrelfy · 17th March 2007, 14:01

That circuit will work EXCEPT...

If you open the door, you'll get a bright LED.

If you have the headlights on and the doors closed, you'll get a dim LED.

If you have the headlights on and you open the door, youll get an even dimmer LED because you have 12V coming down one path being met by X volts coming down the other one.

The resultant voltage is 12v - Xv.

Thats what I think anyway.

Think about it like this, if youve got a remote control and you put both of the batteries in the same way round, it doesnt work does it.

Thats cause youve got 1.5V meeting 1.5V.

17th March 2007, 14:01	#17 (permalink)
itsrelfy Wheelnut Join Date: 19th November 2006 Location: kent Posts: 94 Thanks: 0 Thanked 0 Times in 0 Posts	That circuit will work EXCEPT... If you open the door, you'll get a bright LED. If you have the headlights on and the doors closed, you'll get a dim LED. If you have the headlights on and you open the door, youll get an even dimmer LED because you have 12V coming down one path being met by X volts coming down the other one. The resultant voltage is 12v - Xv. Thats what I think anyway. Think about it like this, if youve got a remote control and you put both of the batteries in the same way round, it doesnt work does it. Thats cause youve got 1.5V meeting 1.5V. Last edited by itsrelfy; 17th March 2007 at 14:04.